uni coursework
#1
l'pool till i die!
Thread Starter
Join Date: Nov 2005
Location: Widnes, UK
Posts: 49
Likes: 0
Received 0 Likes
on
0 Posts
uni coursework
hi guys n gals, could someone give me the basic dimensions of the rotors, eccentric shaft and housings as i am doing some CAD (Computer Aided Design) and want to try and recreate a basic rotary system.
thx for any help.
cheers,
Dave
thx for any help.
cheers,
Dave
#3
Administrator
pages 7-9 here have some info http://www-bsac.eecs.berkeley.edu/pu...calculation%22
some info here
http://72.14.253.104/search?q=cache:...ient=firefox-a
oh this is fun try a=5.99999 b= 3.0 and c=1.5. you can grab the code and look through it plus they have the equation for the epitrochoid right on the page
http://www-groups.dcs.st-and.ac.uk/~...itrochoid.html
some info here
http://72.14.253.104/search?q=cache:...ient=firefox-a
oh this is fun try a=5.99999 b= 3.0 and c=1.5. you can grab the code and look through it plus they have the equation for the epitrochoid right on the page
http://www-groups.dcs.st-and.ac.uk/~...itrochoid.html
#4
Administrator
im going to throw a few more links in here for now.
this one has sizes for various engines includign Mazda 12a and 13b
http://www.rotaryaviation.com/rotaryhistory.htm
ah this has the geometry
http://72.14.253.104/search?q=cache:...ient=firefox-a
etc etc oh i linked the html here is the pdf link.
http://www.personal.utulsa.edu/~kenn...0a%20wankel%22
this one has sizes for various engines includign Mazda 12a and 13b
http://www.rotaryaviation.com/rotaryhistory.htm
ah this has the geometry
http://72.14.253.104/search?q=cache:...ient=firefox-a
7.3 Rotary Engine Geometry
The major elements of the rotary engine–the housing and the rotor– are shown in
cross-section in Figure 7.2. The housing inner surface has a mathematical form known
as a trochoid or epitrochoid. A single-rotor engine housing may be thought of as two
parallel planes separated by a cylinder of epitrochoidal cross-section. Following the
notation of Figure 7.5, the parametric form of the epitrochoid is given by
x = e cos 3
+ Rcos
[ft | m]
(7.1a)
y = e sin 3
+ R sin
[ft | m]
(7.1b)
where e is the eccentricity and R is the rotor center-to-tip distance. For given values of
e and R, Equations (7.1) give the x and y coordinates defining the housing shape when
is varied from 0 to 360 degrees.
The rotor shape may be thought of as an equilateral triangle, as shown in Figures
7.2 and 7.4 (flank rounding and other refinements are discussed later in the chapter).
Because the rotor moves inside the housing in such a way that its three apexes are in
constant contact with the housing periphery, the positions of the tips are also given by
equations of the form of Equations (7.1):
x = e cos 3
+ R cos(
+ 2n
*
/3)
[ft | m]
(7.2a)
y = e sin 3
+ R sin(
+ 2n
*
)
[ft | m]
(7.2b)
where n = 0, 1, or 2, the three values identifying the positions of the three rotor tips,
each separated by 120°. Because R represents the rotor center-to-tip distance, the
otion of the center of the rotor can be obtained from Equations (7.2) by setting R = 0.
The equations and Figure 7.5 indicate that the path of the rotor center is a circle of
radius e.
Note that Equations (7.1) and (7.2) can be nondimensionalized by dividing through
by R. This yields a single geometric parameter governing the equations, e/R, known as
the eccentricity ratio. It will be seen that this parameter is critical to successful
performance of the rotary engine.
The power from the engine is delivered to an external load by a cylindrical shaft.
The shaft axis coincides with the axis of the housing, as seen in Figure 7.2. A second
circular cylinder, the eccentric, is rigidly attached to the shaft and is offset from the
shaft axis by a distance, e, the eccentricity. The rotor slides on the eccentric. Note that
the axes of the rotor and the eccentric coincide. Gas forces exerted on the rotor are
transmitted to the eccentric to provide the driving torque to the engine shaft and to the
external load.
The motion of the rotor may now be understood in terms of the notation of Figure
7.5. The line labeled e rotates with the shaft and eccentric through an angle 3
, while
the line labeled R is fixed to the rotor and turns with it through an angle
about the
moving eccentric center. Thus the entire engine motion is related to the motion of these
two lines. Clearly, the rotor (and thus line R) rotates at one-third of the speed of the
shaft, and there are three shaft rotations for each rotor revolution.
The major elements of the rotary engine–the housing and the rotor– are shown in
cross-section in Figure 7.2. The housing inner surface has a mathematical form known
as a trochoid or epitrochoid. A single-rotor engine housing may be thought of as two
parallel planes separated by a cylinder of epitrochoidal cross-section. Following the
notation of Figure 7.5, the parametric form of the epitrochoid is given by
x = e cos 3
+ Rcos
[ft | m]
(7.1a)
y = e sin 3
+ R sin
[ft | m]
(7.1b)
where e is the eccentricity and R is the rotor center-to-tip distance. For given values of
e and R, Equations (7.1) give the x and y coordinates defining the housing shape when
is varied from 0 to 360 degrees.
The rotor shape may be thought of as an equilateral triangle, as shown in Figures
7.2 and 7.4 (flank rounding and other refinements are discussed later in the chapter).
Because the rotor moves inside the housing in such a way that its three apexes are in
constant contact with the housing periphery, the positions of the tips are also given by
equations of the form of Equations (7.1):
x = e cos 3
+ R cos(
+ 2n
*
/3)
[ft | m]
(7.2a)
y = e sin 3
+ R sin(
+ 2n
*
)
[ft | m]
(7.2b)
where n = 0, 1, or 2, the three values identifying the positions of the three rotor tips,
each separated by 120°. Because R represents the rotor center-to-tip distance, the
otion of the center of the rotor can be obtained from Equations (7.2) by setting R = 0.
The equations and Figure 7.5 indicate that the path of the rotor center is a circle of
radius e.
Note that Equations (7.1) and (7.2) can be nondimensionalized by dividing through
by R. This yields a single geometric parameter governing the equations, e/R, known as
the eccentricity ratio. It will be seen that this parameter is critical to successful
performance of the rotary engine.
The power from the engine is delivered to an external load by a cylindrical shaft.
The shaft axis coincides with the axis of the housing, as seen in Figure 7.2. A second
circular cylinder, the eccentric, is rigidly attached to the shaft and is offset from the
shaft axis by a distance, e, the eccentricity. The rotor slides on the eccentric. Note that
the axes of the rotor and the eccentric coincide. Gas forces exerted on the rotor are
transmitted to the eccentric to provide the driving torque to the engine shaft and to the
external load.
The motion of the rotor may now be understood in terms of the notation of Figure
7.5. The line labeled e rotates with the shaft and eccentric through an angle 3
, while
the line labeled R is fixed to the rotor and turns with it through an angle
about the
moving eccentric center. Thus the entire engine motion is related to the motion of these
two lines. Clearly, the rotor (and thus line R) rotates at one-third of the speed of the
shaft, and there are three shaft rotations for each rotor revolution.
http://www.personal.utulsa.edu/~kenn...0a%20wankel%22
#5
l'pool till i die!
Thread Starter
Join Date: Nov 2005
Location: Widnes, UK
Posts: 49
Likes: 0
Received 0 Likes
on
0 Posts
cheers zoom44; its probably a little more detailed than i needed as only really need to create rotor, eccentric shaft and gear to connect rotor and shaft but s'pose the more detailed the image the better marks i suppose
#7
l'pool till i die!
Thread Starter
Join Date: Nov 2005
Location: Widnes, UK
Posts: 49
Likes: 0
Received 0 Likes
on
0 Posts
Originally Posted by BlueSky
Are you using Solidworks? I took a course in solidworks and its a great program.
#8
l'pool till i die!
Thread Starter
Join Date: Nov 2005
Location: Widnes, UK
Posts: 49
Likes: 0
Received 0 Likes
on
0 Posts
hi does anyone have the dimensions for the renisis or rx7 engine as i seem to have problems with the equations and the diagrams in the links given above, though they have certainly helped, as i generally work better with realistic diagrams.
cheers
cheers
Thread
Thread Starter
Forum
Replies
Last Post
Curtis f
Series I Tech Garage
53
10-04-2017 01:46 AM
truemagellen
Series I Wheels, Tires, Brakes & Suspension
1
11-07-2004 03:50 PM
titaniumgrey
Series I Wheels, Tires, Brakes & Suspension
9
09-06-2004 10:38 PM