Need help from Dyno/Auto Math Experts
#1
Registered User
Thread Starter
Join Date: Nov 2003
Location: Pennsylvania
Posts: 613
Likes: 0
Received 0 Likes
on
0 Posts
Need help from Dyno/Auto Math Experts
I am having friendly argument with one of my professors about calculating horsepower at the wheels. I dyno'd my 240sx last semester and got peak reading of 102 hp and 163 lb/ft at the wheels. Do these numbers seem odd? I think so. A factory 240sx makes approximately 125 hp and 135 lb/ft to the wheels. It seemed funny to me that my car makes 28 lb/ft more than stock, but 23 hp less.
I know all about how a dyno works because I've been trained to use them. I figured there was an error in the software for the measured torque to respective horsepower calculation. To test my theory, I took several of my data points and calculated the horsepower by hand using: HP= (torque x rpm) / 5252. Using this equation, I got results that average about 35% higher than the dyno calculations. My new peak wheel horsepower was 137, which seems to make a lot more sense.
Now comes the argument. My professor feels that the equation I used is not applicable because it was designed for converting measured torque at the flywheel. I agree that the equation is meant for that purpose, but think that it shouldn't matter. If that equation finds a car to have 20% more hp than torque at the flywheel, would that car not still have the same 20% more ratio at the wheels? He believes that the dyno is correct and that I would need a horsepower equation which contained the rpm signal from the roller sensor on the dyno (not the engine rpm), my final drive ratio, and my wheel diameter. I do not know of any such equation.
I know all about how a dyno works because I've been trained to use them. I figured there was an error in the software for the measured torque to respective horsepower calculation. To test my theory, I took several of my data points and calculated the horsepower by hand using: HP= (torque x rpm) / 5252. Using this equation, I got results that average about 35% higher than the dyno calculations. My new peak wheel horsepower was 137, which seems to make a lot more sense.
Now comes the argument. My professor feels that the equation I used is not applicable because it was designed for converting measured torque at the flywheel. I agree that the equation is meant for that purpose, but think that it shouldn't matter. If that equation finds a car to have 20% more hp than torque at the flywheel, would that car not still have the same 20% more ratio at the wheels? He believes that the dyno is correct and that I would need a horsepower equation which contained the rpm signal from the roller sensor on the dyno (not the engine rpm), my final drive ratio, and my wheel diameter. I do not know of any such equation.
#4
U-Stink-But-I-♥-U
iTrader: (1)
Join Date: Mar 2005
Location: 12 o'clock on the Beltway.
Posts: 2,004
Likes: 0
Received 1 Like
on
1 Post
Originally Posted by zoom44
the dyno measures the hp at the wheels and the calculates the T. where did your new hp number come from?
what kind of dyno?
what kind of dyno?
#6
U-Stink-But-I-♥-U
iTrader: (1)
Join Date: Mar 2005
Location: 12 o'clock on the Beltway.
Posts: 2,004
Likes: 0
Received 1 Like
on
1 Post
If I understand. He took the graph ang guessed at # then applied the equation and saw that his # did not match the HP graph. Again, I could be wrong here. If that is what he did, the equation applies as long as you say "to the wheels" Torque to the wheels, HP to the wheels.
EDIT: actually it reads as if he had the raw # and did the calc from those.
EDIT: actually it reads as if he had the raw # and did the calc from those.
#7
Registered User
Thread Starter
Join Date: Nov 2003
Location: Pennsylvania
Posts: 613
Likes: 0
Received 0 Likes
on
0 Posts
It was a Mustang Chassis Dynamometer, which is an electric brake dyno. The dyno puts a specific resistance on the rollers based off of the hp required to keep the vehicle moving at 50 mph and the vehicle's weight. This is done via the PAU, which acts like a generator to create resistance on the rollers. There are two sensors which monitor the rollers. One is a magnetic pickup which reports roller speed (used for ¼ mile runs or test that require a vehicle to maintain a specific speed…like a 50/15 emissions test). The other is a load sensor which reports how much force is absorbed through the PAU. Since the PAU is magnetically pushing in one direction, but is magnetically pushed back on when the rollers are in motion, the PAU case physically rotates. The degree of rotation is converted into a respective torque value. This number is then calculated into a horsepower figure. No dyno measures hp, it is simply a calculated value.
Basically, what I'm asking is if a torque to hp equation at the motor will work for at the wheels?
Edit: becasue torque is measued and hp is calculated, I took the measured torque value of the dyno and calculated hp by hand to see if it match what the dyno calculated. My hp # where 35% higher.
Basically, what I'm asking is if a torque to hp equation at the motor will work for at the wheels?
Edit: becasue torque is measued and hp is calculated, I took the measured torque value of the dyno and calculated hp by hand to see if it match what the dyno calculated. My hp # where 35% higher.
Last edited by s13lover; 01-30-2006 at 05:38 PM.
#9
Administrator
Originally Posted by s13lover
but is magnetically pushed back on when the rollers are in motion, the PAU case physically rotates. The degree of rotation is converted into a respective torque value. This number is then calculated into a horsepower figure.
is that correct?^
#10
Registered
iTrader: (1)
Join Date: May 2003
Location: PA
Posts: 3,754
Likes: 0
Received 0 Likes
on
0 Posts
Originally Posted by s13lover
He believes that the dyno is correct and that I would need a horsepower equation which contained the rpm signal from the roller sensor on the dyno (not the engine rpm), my final drive ratio, and my wheel diameter. I do not know of any such equation.
#11
Registered User
Thread Starter
Join Date: Nov 2003
Location: Pennsylvania
Posts: 613
Likes: 0
Received 0 Likes
on
0 Posts
Originally Posted by carbonRX8
That sounds like a different question. Are you asking if you can convert torque "at the wheels" to HP "at the wheels" and use HP=(tq*rpm)/5252?
#12
Registered User
Thread Starter
Join Date: Nov 2003
Location: Pennsylvania
Posts: 613
Likes: 0
Received 0 Likes
on
0 Posts
Originally Posted by zoom44
the T in this case is the T applied to the PAU by the roller. the calculation is done to find how much power the car has to applyto the roller in order to get that T reading from the PAU. then the T of the car is calculated from the HP of the car.
is that correct?^
is that correct?^
As a side note, this is how you can "cheat" a dyno. If you tell the PAU not to put any resistance on the rollers, it will not rotate because it is not connected to the rollers via magnetism. This will yield very high hp #'s but super low torque #'s (to a point). The opposite is also true. If excess resistance is exerted by the PAU, then you get lower hp #'s but higher torque #'s (to a point).
#13
Registered
iTrader: (1)
Join Date: May 2003
Location: PA
Posts: 3,754
Likes: 0
Received 0 Likes
on
0 Posts
power is conserved through gearing while torque is multiplied through gearing...
so if you have 200 hp at the crank at 5252 rpms at the crank, then you have 200 lbft of torque at the flywheel...
go back to the wheels and go through a 2.5:1 gear and a 4:1 rear gear at the same engine rpms... you now will show 2000 lbft of torque at the wheels (assuming no losses for ease of calculation), but your speed is reduced by a factor of 10 so the rpms of the wheels is only 525.2 rpms - so you still have 200 hp
as you can see you can't take wheel torque and multiply for engine rpm
so if you have 200 hp at the crank at 5252 rpms at the crank, then you have 200 lbft of torque at the flywheel...
go back to the wheels and go through a 2.5:1 gear and a 4:1 rear gear at the same engine rpms... you now will show 2000 lbft of torque at the wheels (assuming no losses for ease of calculation), but your speed is reduced by a factor of 10 so the rpms of the wheels is only 525.2 rpms - so you still have 200 hp
as you can see you can't take wheel torque and multiply for engine rpm
Last edited by r0tor; 01-30-2006 at 06:49 PM.
#14
Administrator
wouldnt this
be the cause of your issue in the first place? why bother with the numbers at all? they are suspect until the dyno is calibrated and so shouldnt be used to derive anything with any of them
Originally Posted by s13lover
If excess resistance is exerted by the PAU, then you get lower hp #'s but higher torque #'s (to a point).
#15
Registered User
Thread Starter
Join Date: Nov 2003
Location: Pennsylvania
Posts: 613
Likes: 0
Received 0 Likes
on
0 Posts
Originally Posted by zoom44
wouldnt this
be the cause of your issue in the first place? why bother with the numbers at all? they are suspect until the dyno is calibrated and so shouldnt be used to derive anything with any of them
be the cause of your issue in the first place? why bother with the numbers at all? they are suspect until the dyno is calibrated and so shouldnt be used to derive anything with any of them
#16
Administrator
but you are suggesting the software is not correct. so the numbers you got cannot be used for anything until that is corrected, thats what i meant by calibrated. the numbers are bogus so forget calculating with them.
#17
Registered User
Thread Starter
Join Date: Nov 2003
Location: Pennsylvania
Posts: 613
Likes: 0
Received 0 Likes
on
0 Posts
Originally Posted by r0tor
power is conserved through gearing while torque is multiplied through gearing...
so if you have 200 hp at the crank at 5252 rpms at the crank, then you have 200 lbft of torque at the flywheel...
go back to the wheels and go through a 2.5:1 gear and a 4:1 rear gear at the same engine rpms... you now will show 2000 lbft of torque at the wheels (assuming no losses for ease of calculation), but your speed is reduced by a factor of 10 so the rpms of the wheels is only 525.2 rpms - so you still have 200 hp
as you can see you can't take wheel torque and multiply for engine rpm
so if you have 200 hp at the crank at 5252 rpms at the crank, then you have 200 lbft of torque at the flywheel...
go back to the wheels and go through a 2.5:1 gear and a 4:1 rear gear at the same engine rpms... you now will show 2000 lbft of torque at the wheels (assuming no losses for ease of calculation), but your speed is reduced by a factor of 10 so the rpms of the wheels is only 525.2 rpms - so you still have 200 hp
as you can see you can't take wheel torque and multiply for engine rpm
#18
Registered User
Thread Starter
Join Date: Nov 2003
Location: Pennsylvania
Posts: 613
Likes: 0
Received 0 Likes
on
0 Posts
Originally Posted by zoom44
but you are suggesting the software is not correct. so the numbers you got cannot be used for anything until that is corrected, thats what i meant by calibrated. the numbers are bogus so forget calculating with them.
#19
Originally Posted by s13lover
It seemed funny to me that my car makes 28 lb/ft more than stock, but 23 hp less.
Originally Posted by s13lover
As a side note, this is how you can "cheat" a dyno. If you tell the PAU not to put any resistance on the rollers, it will not rotate because it is not connected to the rollers via magnetism. This will yield very high hp #'s but super low torque #'s (to a point). The opposite is also true. If excess resistance is exerted by the PAU, then you get lower hp #'s but higher torque #'s (to a point).
#20
Administrator
Michael Caldwell
<michael@mustangdyne.com>to me
More options 6:45 am (39 minutes ago)
Charlie,
Our dynos report delivered force to the drum surface via two direct
measurents - speed/time (acceleration rate) and the force exirted on the
strain guage load cell (torque). Power is a function of force and speed, so
the power reported also involves the instantaneous speed as measured at the
drum. In a static condition (constant speed) torque is obtained from the
voltage output from the load cell and nothing else - when the vehicle is
accelerating a portion of the power will be reported as a function of
acceleration power.
<michael@mustangdyne.com>to me
More options 6:45 am (39 minutes ago)
Charlie,
Our dynos report delivered force to the drum surface via two direct
measurents - speed/time (acceleration rate) and the force exirted on the
strain guage load cell (torque). Power is a function of force and speed, so
the power reported also involves the instantaneous speed as measured at the
drum. In a static condition (constant speed) torque is obtained from the
voltage output from the load cell and nothing else - when the vehicle is
accelerating a portion of the power will be reported as a function of
acceleration power.
so force(T the drum applies against the strain guage) x speed(rpms of the drum) is work over time. Thats Horspower. the dyno is not measuring the car at all. but the first thing it can calculate is the Horsepower the car is applying to the drum.
Then if you know the RPM of the car you can calculate the Torque of the car using
HP=(tq*rpm)/5252
you cannot calculate to find your "true hp" because the Torque number you want to plug in to the equation is not true.
#21
Registered User
Thread Starter
Join Date: Nov 2003
Location: Pennsylvania
Posts: 613
Likes: 0
Received 0 Likes
on
0 Posts
Funny, I emailed Mustang and got a reply from the same guy. However, he gave me a different answer. I ask him if my numbers looked odd and if the math I was using was correct. His response was simply that he needed more information about the edition dyno software I was using before he could make any conclusion.
It seems that if I could get the torque of the drum (not the torque of the car which is what the software outputs) and the speed of the drum then I could use my original HP formula. Now I just have to figure out how to pull those out of the software, or if I even can.
It seems that if I could get the torque of the drum (not the torque of the car which is what the software outputs) and the speed of the drum then I could use my original HP formula. Now I just have to figure out how to pull those out of the software, or if I even can.
#22
Administrator
hehe
i furthur asked
to which he replied
so yes if you had the T measured by the deflection of the pau and the rpm of the drum (actually the shaft is measured) then you could calculate the HP of your car and then with the rpm of your car calculate your T
i furthur asked
So the measurements are A. speed of the drum(constant or accelerating) B.
Force applied by the drum on the Strain guage.
Neither of these is a measure of the power of the car correct? From them
(and the size/mass of the drum) the HP the car is applying to the drum is
calculated? what is that Formula?
Force applied by the drum on the Strain guage.
Neither of these is a measure of the power of the car correct? From them
(and the size/mass of the drum) the HP the car is applying to the drum is
calculated? what is that Formula?
Power = torque (ft-lbs acting on a shaft)* speed (RPM of the same
shaft)/5252. In the case of a chassis dynamometer, the power is measured as
delivered to the drum, so the torque and speed are measured at the drum
shaft.
shaft)/5252. In the case of a chassis dynamometer, the power is measured as
delivered to the drum, so the torque and speed are measured at the drum
shaft.
Thread
Thread Starter
Forum
Replies
Last Post
Shankapotamus3
Series I Trouble Shooting
28
03-14-2021 03:53 PM
Austin22
New Member Forum
5
09-23-2015 04:46 PM