Could you please post or email your schematic to me?
ramonmannella@outlook.com
I am terrible with electronics.... When I hook up 12v to a 1.2k resistor, attach that to the input of the pot followed byanother 1.2k coming out..... I get no change in voltage other than wwhat's tunable via the pot. Am I doing something wrong?
What voltage do the stock sensor send when the car is level?
Thanks again for taking the time to help.

Sorry for the confusion. Hopefully I can clarify.

I replaced the front sensor with the two equal valued resistors. The output voltage to the ECU is 1/2 the input.

I replaced therear sensor with the following: 1.2k Ohm resistor to10k Ohm potentiometer to 1.2k Ohm resistor

The sensor line goes to the tap on the potentiometer as in the schematic. This slight change makes the min and max output voltages match the stock sensor to keep from pushing the leveling motors from trying to exceed their range.

I set the pot. in the middle, and then tweaked from there. I was not concerned with being able to adjust the level from the drivers seat, so I left it in a small plastic project box in the trunk.

Or on the part the circuit that goes to then front giving constant voltage?
Then way the original schematic is designed, I think it splits the voltage in half. Is that correct?
12v in / 6v out?
What does it bring the voltage to adding the 2 resistors?

In the schematic it calls for 2 1k and 2 4.7k as well as a 10k pot.
You used and additional 2 resistors (10k /1.2k) on the output of the pot?
I apologize if I'm not making any sense.

If you refer to the schematic that I linked to in my original post, I used a 10k Ohm resistor followed by a 1.2k Ohm to give a total of 11.2k Ohm on that part of the circuit. I can post a picture and my version of the schematic this weekend.